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Chemistry

Name the organic compound prepared by each of the following reactions :

(i) C2H5COONa + NaOH ⟶

(ii) CH3I + 2[H]⟶

(iii) C2H5Br + KOH (alcoholic soln.) ⟶

(iv) CaC2 + 2H2O ⟶

Organic Chemistry

ICSE

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Answer

(i) Ethane

C2H5COONasodium propionate+NaOHsodalimeCaOΔC2H6ethane+Na2CO3\underset{\text{sodium propionate}}{\text{C}2\text{H}5\text{COONa}} + \underset{\text{sodalime}}{\text{NaOH}} \underset{\Delta}{\xrightarrow{\text{CaO}}} \underset{\text{ethane}}{\text{C}2\text{H}6} + \text{Na}2\text{CO}3

(ii) Methane

CH3Imethyl iodide+2[H]nascent hydrogenalcoholZn/Cu coupleCH4methane+HI\underset{\text{methyl iodide}}{\text{CH}3\text{I}} + \underset{\text{nascent hydrogen}}{2\text{[H]}} \xrightarrow[\text{alcohol}]{\text{Zn/Cu couple}} \underset{\text{methane}}{\text{CH}4} +\text{HI}

(iii) Ethene [ethylene]

C2H5Br Bromo ethane [ethyl bromide]+KOHalcoholicboilH2C=CH2ethene [ethylene]+KBr+H2O\underset{\text{ Bromo ethane [ethyl bromide]}}{\text{C}2\text{H}5\text{Br}} + \underset{\text{alcoholic}}{\text{KOH}} \xrightarrow{\text{boil}} \underset{\text{ethene [ethylene]}}{\text{H}2\text{C}=\text{C}\text{H}2} + \text{KBr} + \text{H}_2\text{O}

(iv) Ethyne [Acetylene]

CaC2calcium carbide+2H2OwaterC2H2ethyne [acetylene]+Ca(OH)2\underset{\text{calcium carbide}}{\text{CaC}2} + \underset{\text{water}}{2\text{H}2\text{O}} \longrightarrow \underset{\text{ethyne [acetylene]}}{\text{C}2\text{H}2} + \text{Ca(OH)}_2

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