Let the resistance of an electrical component remain constant while the potential difference across the two ends of the component decreases to half of its former value. What change will occur in the current through it?

According to Ohm's Law:

I = $\dfrac{\text{V}}{\text{R}}$

Given, the potential difference decreases to half of its former value, keeping the resistance constant

V₂ = $\dfrac{\text{V}}{2}$ , R₂ = R, I₂ = ?

Substituting the values we get,

I₂ = $\dfrac{\text{V}}{2\text{R}}$ = $\dfrac{\text{I}_1}{2}$

Therefore, the current flowing through the electrical component is reduced by half.