KnowledgeBoat Logo

Mathematics

In triangle ABC, ∠ABC = 90°, side AB = 6 cm, side BC = 7.2 cm and BD is perpendicular to side AC. Draw circumcircle of triangle BDC and then state the length of the radius of this circumcircle drawn.

Constructions

4 Likes

Answer

Steps of construction :

  1. Draw BC = 7.2 cm.

  2. Draw a ray BX, such that ∠XBC = 90°.

  3. With B as center and radius = 6 cm cut an arc on BX and mark point A.

  4. Join AC.

  5. Take a point D on AC such that BD ⊥ AC.

  6. Draw perpendicular bisectors of BD and BC which intersect at I.

  7. With I as center and IC as radius draw a circle passing through B, D and C. Measure IC.

In triangle ABC, ∠ABC = 90°, side AB = 6 cm, side BC = 7.2 cm and BD is perpendicular to side AC. Draw circumcircle of triangle BDC and then state the length of the radius of this circumcircle drawn. Constructions, Concise Mathematics Solutions ICSE Class 10.

Hence, above is the required circumcircle with radius = 3.6 cm.

Answered By

2 Likes


Related Questions