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In the figure (1) given below, find the value of x.

In the figure (1) given below, find the value of x. Triangles, ML Aggarwal Understanding Mathematics Solutions ICSE Class 9.

Triangles

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Answer

From figure,

In the figure (1) given below, find the value of x. Triangles, ML Aggarwal Understanding Mathematics Solutions ICSE Class 9.

∠ABD = ∠BAD = 36° (As angles opposite to equal sides are equal.)

∠BDA = 180° - (36° + 36°) = 180° - 72° = 108°.

From figure,

∠BDA + ∠ADC = 180°

108° + ∠ADC = 180°

∠ADC = 72°.

In △ADC,

As AD = AC,

∴ ∠ADC = ∠ACD = 72° (As angles opposite to equal sides are equal.)

∠ADC + ∠ACD + ∠DAC = 180°

72° + 72° + ∠DAC = 180°

∠DAC = 180° - 144° = 36°.

From figure,

∠BAD + ∠DAC + x = 180°

36° + 36° + x = 180°

72° + x = 180°

x = 108°.

Hence, x = 108°.

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