Mathematics
In the adjoining figure, two chords AB and CD of a circle intersect at P. If AB = CD, prove that arc AD = arc CB.
Circles
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Answer
Given AB = CD
Since, in a circle, equal chords cut off equal arcs.
∴ arc AB = arc CD
Subtracting arc BD from both sides we get,
⇒ arc AB - arc BD = arc CD - arc BD
⇒ arc AD = arc CB.
Hence, proved that arc AD = arc CB.
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