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In the adjoining figure, ∠BEC = 125° and ∠ACD = 25°; then the angle BAC is :

  1. 100°

  2. 110°

  3. 90°

  4. 65°

In the adjoining figure, ∠BEC = 125° and ∠ACD = 25°; then the angle BAC is : 1. 100° 2. 110° 3. 90° 4. 65°. Model Paper 5, Concise Mathematics Solutions ICSE Class 10.

Circles

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Answer

From figure,

⇒ ∠BEC + ∠DEC = 180° (Linear pairs)

⇒ 125° + ∠DEC = 180°

⇒ ∠DEC = 180° - 125° = 55°.

In △DEC,

⇒ ∠DEC + ∠ECD + ∠CDE = 180°

⇒ 55° + 25° + ∠CDE = 180°

⇒ ∠CDE = 180° - 55° - 25° = 100°.

From figure,

∠BDC = ∠CDE = 100°

We know that,

Angles subtended by same segment of the circle are equal.

∴ ∠BAC = ∠BDC = 100°.

Hence, Option 1 is the correct option.

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