In ∆ABC, ∠A = 90°. If AB = 7 cm and BC - AC = 1 cm, find : (i) sin C (ii) tan B

(a) In right ∆ABC ∠A = 90° AB = 7 cm BC - AC = 1 cm ⇒ BC = 1 + AC We know that, ⇒ BC 2 = AB 2 + AC 2 [By pythagoras theorem] ⇒ (1 + AC) 2 = AB 2 + AC 2 ⇒ 1 + AC 2 + 2AC = 7 2 + AC 2 ⇒ 1 + AC 2 + 2AC = 49 + AC 2 ⇒ 2AC = 49 - 1 ⇒ 2AC = 48 ⇒ AC = = 24 cm. ∴ BC = 1 + AC = 25 cm. (i) sin C = = Hence, sin C = . (ii) tan B = = Hence, tan B = .

In the figure (2) given below, ∆ABC is right-angled at B. If AB = y units, BC = 3 units and CA = 5 units, find
(i) sin x°
(ii) y.

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In △PQR, ∠Q = 90°. If PQ = 40 cm and PR + QR = 50 cm, find :
(i) sin P
(ii) cos P
(iii) tan R

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In △ABC, AB = AC = 15 cm, BC = 18 cm. Find
(i) cos ∠ABC
(ii) sin ∠ACB.

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Mathematics

In ∆ABC, ∠A = 90°. If AB = 7 cm and BC - AC = 1 cm, find :
(i) sin C
(ii) tan B

Trigonometrical Ratios

Related Questions

In the figure (2) given below, ∆ABC is right-angled at B. If AB = y units, BC = 3 units and CA = 5 units, find
(i) sin x°
(ii) y.

In △PQR, ∠Q = 90°. If PQ = 40 cm and PR + QR = 50 cm, find :
(i) sin P
(ii) cos P
(iii) tan R

In △ABC, AB = AC = 15 cm, BC = 18 cm. Find
(i) cos ∠ABC
(ii) sin ∠ACB.

Mathematics

In ∆ABC, ∠A = 90°. If AB = 7 cm and BC - AC = 1 cm, find :(i) sin C(ii) tan B

Trigonometrical Ratios

Related Questions

In the figure (2) given below, ∆ABC is right-angled at B. If AB = y units, BC = 3 units and CA = 5 units, find(i) sin x°(ii) y.

In △PQR, ∠Q = 90°. If PQ = 40 cm and PR + QR = 50 cm, find :(i) sin P(ii) cos P(iii) tan R

In △ABC, AB = AC = 15 cm, BC = 18 cm. Find(i) cos ∠ABC(ii) sin ∠ACB.

In ∆ABC, ∠A = 90°. If AB = 7 cm and BC - AC = 1 cm, find :
(i) sin C
(ii) tan B

In the figure (2) given below, ∆ABC is right-angled at B. If AB = y units, BC = 3 units and CA = 5 units, find
(i) sin x°
(ii) y.

In △PQR, ∠Q = 90°. If PQ = 40 cm and PR + QR = 50 cm, find :
(i) sin P
(ii) cos P
(iii) tan R

In △ABC, AB = AC = 15 cm, BC = 18 cm. Find
(i) cos ∠ABC
(ii) sin ∠ACB.