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In a pentagon ABCDE, AB is parallel to DC and ∠A : ∠E : ∠D = 3 : 4 : 5. Find angle E.

Rectilinear Figures

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Answer

In a pentagon ABCDE, AB is parallel to DC and ∠A : ∠E : ∠D = 3 : 4 : 5. Find angle E. Rectilinear Figures, Concise Mathematics Solutions ICSE Class 9.

By formula,

Sum of interior angles of an 'n' sided polygon = (2n - 4) × 90°.

Sum of interior angles of 5 sided polygon = [2 × 5 - 4] × 90°

= [10 - 4] × 90°

= 6 × 90°

= 540°.

We know that,

Sum of interior angles on the same side of transversal are supplementary.

∴ ∠B + ∠C = 180°.

Given,

∠A : ∠E : ∠D = 3 : 4 : 5

Let ∠A = 3x, ∠E = 4x and ∠D = 5x.

∴ ∠A + ∠B + ∠C + ∠D + ∠E = 540°

⇒ 3x + 180° + 5x + 4x = 540°

⇒ 12x = 540° - 180°

⇒ 12x = 360°

⇒ x = 360°12\dfrac{360°}{12} = 30°.

⇒ ∠E = 4x = 4(30°) = 120°.

Hence, ∠E = 120°.

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