In a conductor, 6.25 × 10¹⁶ electrons flow from it's end A to B in 2 s. Find the current flowing through the conductor. (e = 1.6 × 10^-19 C)

Given,

Number of electrons flowing (n) = 6.25 × 10¹⁶

Time taken (t) = 2 s

e = 1.6 × 10^-19 C

Current in conductor is given by,

$\text{I} = \dfrac{\text{ne}}{\text{t}}$

Substituting the values in the formula above we get,

$I = \dfrac{6.25 \times 10^{16} \times 1.6 \times 10^{-19}}{2} \\[0.5em] I = \dfrac{6.25 \times 1.6 \times 10^{-3}}{2} \\[0.5em] I = 6.25 \times 0.8 \times 10^{-3} \\[0.5em] I = 5 \times 10^{-3} A$

Hence, the current flowing through the conductor = 5 mA from B to A