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Mathematics

In a bundle of 50 shirts, 44 are good, 4 have minor defects and 2 have major defects. What is the probability that :

(i) it is acceptable to a trader who accepts only a good shirt ?

(ii) it is acceptable to a trader who rejects only a shirt with major defects ?

Probability

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Answer

We have,

Total number of shirts = 50

∴ No. of possible outcomes = 50.

(i) As, trader accepts only good shirts and number of good shirts = 44.

∴ No. of favourable outcomes = 44

P(trader will accept) = No. of favourable outcomesNo. of possible outcomes=4450=2225\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{44}{50} = \dfrac{22}{25}.

Hence, the probability that a shirt is acceptable to a trader who accepts only a good shirt = 2225\dfrac{22}{25}.

(ii) As, trader rejects shirts with major defects only and number of shirts with major defects = 2.

No. of shirts that trader will accept = 50 - 2 = 48.

∴ No. of favourable outcomes = 48

P(trader will accept) = No. of favourable outcomesNo. of possible outcomes=4850=2425\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{48}{50} = \dfrac{24}{25}.

Hence, the probability that a shirt is acceptable to a trader who rejects only a shirt with major defects = 2425\dfrac{24}{25}.

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