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If [2b89a+b]=[6898]\begin{bmatrix}[r] 2b & 8 \ 9 & a + b \end{bmatrix} = \begin{bmatrix}[r] 6 & 8 \ 9 & 8 \end{bmatrix}, then the value of a is :

  1. 5

  2. 11

  3. 8

  4. 9

Matrices

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Answer

Given,

[2b89a+b]=[6898]\begin{bmatrix}[r] 2b & 8 \ 9 & a + b \end{bmatrix} = \begin{bmatrix}[r] 6 & 8 \ 9 & 8 \end{bmatrix}

From above,

⇒ 2b = 6

⇒ b = 62\dfrac{6}{2} = 3.

Also,

⇒ a + b = 8

⇒ a + 3 = 8

⇒ a = 8 - 3 = 5.

Hence, Option 1 is the correct option.

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