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If the weight of a body in air is W1, in a liquid is W2 and in water is W3, then :

  1. R.D. of liquid = W2W3W1W3\dfrac{\text{W}2 - \text{W}3}{\text{W}1 - \text{W}3}

  2. R.D. of liquid = W1W2W1W3\dfrac{\text{W}1 - \text{W}2}{\text{W}1 - \text{W}3}

  3. R.D. of liquid = W2W3W1+W3\dfrac{\text{W}2 - \text{W}3}{\text{W}1 + \text{W}3}

  4. R.D. of liquid = W1W2W1+W3\dfrac{\text{W}1 - \text{W}2}{\text{W}1 + \text{W}3}

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Answer

R.D. of liquid = W1W2W1W3\dfrac{\text{W}1 - \text{W}2}{\text{W}1 - \text{W}3}

Reason — R.D. of liquid = Weight of liquid displaced by a bodyWeight of water displaced by the same body\dfrac{\text{Weight of liquid displaced by a body}}{\text{Weight of water displaced by the same body}}

R.D. of liquid = Weight of body in air (W)1Weight of body in liquid (W)2Weight of body in air (W)1Weight of body in water (W)3\dfrac{\text{Weight of body in air (W)}1 - \text{Weight of body in liquid (W)}2}{\text{Weight of body in air (W)}1 - \text{Weight of body in water (W)}3}

Thus,

R.D. of liquid = W1W2W1W3\dfrac{\text{W}1 - \text{W}2}{\text{W}1 - \text{W}3}

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