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If the volume of a cube is V m3, its surface area is S m2 and the length of a diagonal is d metres, prove that 636\sqrt{3} V = Sd.

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Answer

Let side of cube = a m.

By formula,

Volume of cube (V) = (side)3 = a3,

Surface area (S) = 6(side)2 = 6a2.

Length of diagonal (d) = 3\sqrt{3} side = 3a\sqrt{3}a.

63V=63×a3=63a3Sd=6a2×3a=63a3.\Rightarrow 6\sqrt{3}V = 6\sqrt{3} \times a^3 = 6\sqrt{3}a^3 \\[1em] \Rightarrow Sd = 6a^2 \times \sqrt{3}a = 6\sqrt{3}a^3.

63V=Sd=63a3.6\sqrt{3} V = Sd = 6\sqrt{3}a^3.

Hence, proved that 636\sqrt{3} V = Sd.

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