If the equation (k + 1)x 2 - 2(k - 1)x + 1 = 0 has equal roots, then the values of k are 1. 1, 3 2. 0, 3 3. 0, 1 4. 0,

Given , (k + 1)x 2 - 2(k - 1)x + 1 = 0 has equal roots Comparing equation with ax 2 + bx + c = 0 a= (k + 1) , b = -2(k - 1) , c = 1 Since, equation has equal roots ∴ b 2 - 4ac = 0 ∴ Option 2 is the correct option.