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Chemistry

If the empirical formula of a compound is CH and it has a vapour density of 13, find the molecular formula of the compound.

[C = 12, H = 1]

Stoichiometry

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Answer

Empirical formula is CH

Empirical formula weight = 12 + 1 = 13

Vapour density (V.D.) = 13

Molecular weight = 2 x V.D. = 2 x 13

n=Molecular weightEmpirical formula weight=2×1313=2\text{n} = \dfrac{\text{Molecular weight}}{\text{Empirical formula weight}} \\[0.5em] = \dfrac{2 \times 13}{13} = 2

∴ Molecular formula = n[E.F.] = 2[CH] = C2H2

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