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Mathematics

If the classes of a frequency distribution are 1 - 10, 11 - 20, 21 - 30, …., 51 - 60, then the size of each class is

  1. 9

  2. 10

  3. 11

  4. 5.5

Measures of Central Tendency

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Answer

On converting the class from discontinuous intervals into continuous intervals.

Adjustment factor = (Lower limt of one class - Upper limit of previous class) / 2

=11102=12=0.5= \dfrac{11 - 10}{2} \\[1em] = \dfrac{1}{2} \\[1em] = 0.5

Classes before adjustmentClasses after adjustment
1 - 100.5 - 10.5
11 - 2010.5 - 20.5
21 - 3020.5 - 30.5
31 - 4030.5 - 40.5
41 - 5040.5 - 50.5
51 - 6050.5 - 60.5

Class interval = 10.5 - 0.5 = 10.

Hence, Option 2 is the correct option.

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