If tan θ = $\dfrac{5}{12}$, find the value of $\dfrac{\text{(cos θ + sin θ)}}{\text{(cos θ - sin θ)}}$.

Solving,

$\Rightarrow \dfrac{\text{(cos θ + sin θ)}}{\text{(cos θ - sin θ)}} \\[1em] [\text{Dividing numerator and denominator by cos θ}] \\[1em] \Rightarrow \dfrac{\dfrac{\text{(cos θ + sin θ)}}{\text{cos θ}}}{\dfrac{\text{(cos θ - sin θ)}}{\text{cos θ}}} \\[1em] \Rightarrow \dfrac{\dfrac{\text{cos θ}}{\text{cos θ}} + \dfrac{\text{sin θ}}{\text{cos θ}}}{\dfrac{\text{cos θ}}{\text{cos θ}} - \dfrac{\text{sin θ}}{\text{cos θ}}} \\[1em] \Rightarrow \dfrac{1 + \text{tan θ}}{1 - \text{tan θ}} [\text{As tan θ} = \dfrac{\text{sin θ}}{\text{cos θ}}] \\[1em] \text{Substituting values we get} \\[1em] \Rightarrow \dfrac{1 + \dfrac{5}{12}}{1 - \dfrac{5}{12}} \\[1em] \Rightarrow \dfrac{\dfrac{12 + 5}{12}}{\dfrac{12 - 5}{12}} \\[1em] \Rightarrow \dfrac{\dfrac{17}{12}}{\dfrac{7}{12}} \\[1em] \Rightarrow \dfrac{17}{7} = 2\dfrac{3}{7}.$

Hence, $\dfrac{\text{(cos θ + sin θ)}}{\text{(cos θ - sin θ)}} = 2\dfrac{3}{7}$.