If sin θ = , then cos θ is equal to 1. b/√b^2-a^2 2. b/a 3. √b^2-a^2/b 4. a/√b^2-a^2

Let ABC be a right angle triangle with ∠B = 90° and ∠C = θ. By formula, sin θ = Substituting values we get : Let AB = ak and AC = bk. In right angle triangle ABC, ⇒ AC 2 = AB 2 + BC 2 ⇒ (bk) 2 = (ak) 2 + BC 2 ⇒ b 2 k 2 = a 2 k 2 + BC 2 ⇒ BC 2 = b 2 k 2 - a 2 k 2 ⇒ BC 2 = ⇒ BC = . By formula, Hence, Option 3 is the correct option.