If one end of a diameter of a circle is (2,3) and the centre is (-2, 5), then the other end is

1. (-6, 7)

2. (6, -7)

3. (0, 8)

4. (0, 4)

Let B(x, y) be the other end of the diameter, whose one end is A(2, 3)

∴ The mid-point of AB is $\Big(\dfrac{x + 2}{2}, \dfrac{y + 3}{2}\Big)$

The center of the circle is (-2, 5).

Since, the centre of the circle is the mid-point of AB,

$\Rightarrow \dfrac{2 + x}{2} = -2 \text{ and } \dfrac{y + 3}{2} = 5 \\[1em] \Rightarrow 2 + x = -4 \text{ and } y + 3 = 10 \\[1em] \Rightarrow x = -4 - 2 \text{ and } y = 10 - 3 \\[1em] \Rightarrow x = -6 \text{ and } y = 7.$

∴ Coordinates of other end are (-6, 7).

Hence, Option 1 is the correct option.