If k, 2(k + 1), 3(k + 1) are three consecutive terms of a G.P., then the value of k is
-1
-4
1
4
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The 5th term from the end of the G.P. 2, 6, 18, …., 13122 is
162
486
54
1458
Write the first four terms of the A.P. when its first term is -5 and common difference is -3.