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In △ABC,
⇒ ∠A + ∠B + ∠C = 180°
⇒ ∠A + ∠B + 90° = 180°
⇒ ∠A + ∠B = 90°.
⇒ cos (A + B) = cos 90° = 0.
Hence, Option 1 is the correct option.
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In the adjoining figure, PQR is a right triangle right angled at Q. If PQ = 4 cm and PR = 8 cm then ∠P is equal to
60°
45°
30°
15°
