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Mathematics

If a = log23\dfrac{2}{3}, b = log35\dfrac{3}{5} and c = 2log52\sqrt{\dfrac{5}{2}}, find the value of

(i) a + b + c

(ii) 5a + b + c

Logarithms

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Answer

(i) Given,

a+b+c=log 23+log 35+2log 52=log 2 - log 3 + log 3 - log 5+2×log(52)12=log 2log 5+2×12×(log 5 - log 2)=log 2 - log 5 + log 5 - log 2=0.\Rightarrow a + b + c = \text{log }\dfrac{2}{3} + \text{log }\dfrac{3}{5} + 2\text{log }\sqrt{\dfrac{5}{2}} \\[1em] = \text{log 2 - log 3 + log 3 - log 5} + 2 \times \text{log}\Big(\dfrac{5}{2}\Big)^{\dfrac{1}{2}} \\[1em] = \text{log } 2 - \text{log } 5 + 2 \times \dfrac{1}{2} \times \text{(log 5 - log 2)} \\[1em] = \text{log 2 - log 5 + log 5 - log 2} \\[1em] = 0.

Hence, a + b + c = 0.

(ii) Given,

⇒ 5a + b + c = 50 = 1.

Hence, 5a + b + c = 1.

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