Mathematics

If a kite is flying at a height of $40\sqrt{3}$ meters from the level ground, attached to a string inclined at 60° to the horizontal, then the length of the string is
80 m
$60 \sqrt{3}$ m
$80\sqrt{3}$ m
120 m.

Heights & Distances

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Answer

Let the kite be at point B.

If a kite is flying at a height of 40√3 meters from the level ground, attached to a string inclined at 60° to the horizontal, then the length of the string is. Heights and Distances, ML Aggarwal Understanding Mathematics Solutions ICSE Class 10.

Considering right angled △ABC we get,

$\text{sin 60} = \dfrac{BC}{AB} \\[1em] \dfrac{\sqrt{3}}{2} = \dfrac{40\sqrt{3}}{AB} \\[1em] AB = \dfrac{40 \sqrt{3} \times 2}{\sqrt{3}} \\[1em] AB = 80$

Hence, Option 1 is the correct option.

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If a kite is flying at a height of 40340\sqrt{3}403​ meters from the level ground, attached to a string inclined at 60° to the horizontal, then the length of the string is80 m60360 \sqrt{3}603​ m80380\sqrt{3}803​ m120 m.

Heights & Distances

Answer

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