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If a is the root of the equation x2 - (a + b)x + k = 0, find the value of k.

Quadratic Equations

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Answer

Since, a is the root of the equation x2 - (a + b)x + k = 0 , x = a satisfies the given equation.

Substituting x = a in the given equation:

a2(a+b)a+k=0a2(a2+ab)+k=0a2a2ab+k=0kab=0k=ab\Rightarrow a^2 - (a+b)a + k = 0 \\[0.5em] \Rightarrow a^2 - (a^2 + ab) + k = 0 \\[0.5em] \Rightarrow a^2 - a^2 - ab + k = 0 \\[0.5em] \Rightarrow k - ab = 0 \\[0.5em] \Rightarrow k = ab

Hence, the value of k is ab.

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