Physics
How would you connect two resistors in series? Draw a diagram. Calculate the total equivalent resistance.
Current Electricity
51 Likes
Answer
Below diagram shows two resistors connected in series:

If current I is drawn from the battery, the current through each resistor will also be I.
By Ohm's law,
p.d. between A and B is V1 = VA - VB = IR1
p.d. between B and C is V2 = VB - VC = IR2
Adding these we get,
V = V1 + V2
= VA - VB + VB - VC
= VA - VC
= IR1 + IR2
= I (R1 + R2) [Equation 1]
If the equivalent resistance between the points A and C is RS, then the potential difference between the points A and C is
V = VA - VC = IRS [Equation 2]
Therefore from equation 1 and 2,
IRS = I (R1 + R2)
⇒ RS = R1 + R2
Thus, in the series combination, the equivalent resistance is equal to the sum of the individual resistances.
Answered By
26 Likes
Related Questions
Explain the meaning of the terms e.m.f., terminal voltage and internal resistance of a cell.
Explain why is the p.d. across the terminals of a cell is more in an open circuit and reduced in a closed circuit.
Show by a diagram how two resistors R1 and R2 are joined in parallel. Obtain an expression for the total resistance of combination.
The diagram in figure shows a cell of e.m.f. ε = 2 volt and internal resistance r = 1 ohm connected to an external resistance R = 4 ohm. The ammeter A measures the current in the circuit and the voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when (i) the key K is open, and (ii) the key K is closed.