KnowledgeBoat Logo

Chemistry

How are the following conversions carried out:

(i) Ethyl chloride to Ethyl alcohol.

(ii) Ethyl chloride to Ethene.

(iii) Ethene to Ethyl alcohol.

(iv) Ethyl alcohol to Ethene.

Organic Chemistry

23 Likes

Answer

(i) By boiling ethyl chloride with aqueous NaOH.

C2H5-Cl Chloroethane [ethyl chloride]+NaOH [aq.]boilC2H5OH Ethanol [ethyl alcohol]+NaCl\underset{\text{ Chloroethane [ethyl chloride]}}{\text{C}2\text{H}5\text{-Cl}} + \text{NaOH [aq.]} \xrightarrow{\text{boil}} \underset{\text{ Ethanol [ethyl alcohol]}}{\text{C}2\text{H}5\text{OH}} + \text{NaCl}

(ii) By boiling ethyl chloride with alcoholic KOH.

C2H5-Cl Chloroethane [ethyl chloride]+KOH [aq.] alcoholic KOHboilC2H4 Ethene [ethylene]+KCl+H2O\underset{\text{ Chloroethane [ethyl chloride]}}{\text{C}2\text{H}5\text{-Cl}} + \underset{\text{ alcoholic KOH}}{\text{KOH [aq.]}} \xrightarrow{\text{boil}} \underset{\text{ Ethene [ethylene]} }{\text{C}2\text{H}4} + \text{KCl} +\text{H}_2\text{O}

(iii) Ethene is absorbed in conc. sulphuric acid at 80 °C under 30 atmos. to give ethyl hydrogen sulphate, which on hydrolysis with steam gives ethanol.

C2H4 Ethene+H2SO4conc.80°C30 atmos.C2H5-HSO4 Ethyl hydrogen sulphate\underset{\text{ Ethene} }{\text{C}2\text{H}4} + \underset{\text{conc.}}{\text{H}2\text{SO}4} \underset{30 \text{ atmos.}}{\xrightarrow{80 \degree \text{C}}} \underset{\text{ Ethyl hydrogen sulphate} }{\text{C}2\text{H}5\text{-HSO}_4}

C2H5-HSO4 Ethyl hydrogen sulphate +H2OsteamC2H5-OH Ethanol [ethyl alcohol]+H2SO4\underset{\text{ Ethyl hydrogen sulphate }}{\text{C}2\text{H}5\text{-HSO}4} + \underset{\text{steam}}{\text{H}2\text{O}} \longrightarrow \underset{ \text{ Ethanol [ethyl alcohol]} }{\text{C}2\text{H}5\text{-OH}} + \text{H}2\text{SO}4

(iv) By heating ethyl alcohol with concentrated H2SO4 at 170°C.

C2H5OH ethyl alcohol170°CConc. H2SO4[excess]C2H4ethene+H2O\underset{\text{ ethyl alcohol}}{\text{C}2\text{H}5\text{OH}} \xrightarrow[170\degree\text{C}]{\text{Conc. H}2\text{SO}4\text{[excess]}} \underset{ \text{ethene}}{\text{C}2\text{H}4} + \text{H}_2\text{O}\

Answered By

12 Likes


Related Questions