On the same graph paper, draw the straight lines represented by equations:

x = 5, x + 5 = 0, y + 3 = 0 and y = 3.

Also, find the area and perimeter of the rectangle formed by the intersection of these lines.

First equation: x = 5

This is a vertical line parallel to the y-axis and intersects the x-axis at ( x = 5 ).

Second equation: x + 5 = 0

x = -5

This is a vertical line parallel to the y-axis and intersects the x-axis at ( x = -5 ).

Third equation: y + 3 = 0

y = -3

This is a horizontal line parallel to the x-axis and intersects the y-axis at ( y = -3 ).

Fourth equation: y = 3

This is a horizontal line parallel to the x-axis and intersects the y-axis at ( y = 3 ).

The intersection points of these lines will form the vertices of the rectangle:

A = (-5, 3)
B = (5, 3)
C = (5, -3)
D = (-5, -3)

Distance between AB = 10 units, BC = 6 units, CD = 10 units and DA = 6 units.

Perimeter of rectangle = AB + BC + CD + DA

= 10 + 6 + 10 + 6 = 32 units.

Area of rectangle = length x breadth = AB x CD

= 10 x 6 = 60 sq. units

Hence, area of rectangle = 60 sq. units and perimeter = 32 units.