Chemistry
Give two tests for dilute sulphuric acid with balanced equations. State why
(i) BaCl2
(ii) Pb(NO3)2
are used for the above tests
Sulphuric Acid
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Answer
(i) BaCl2 solution on treating with dilute sulphuric acid forms white ppt. of barium sulphate, which is insoluble in dilute sulphuric acid.
BaCl2 + H2SO4 (dil) ⟶ 2HCl + BaSO4 ↓ [white ppt. formed]
(ii) Pb(NO3)2 on treating with dilute sulphuric acid gives white ppt of lead sulphate, which is insoluble in dil. H2SO4.
Pb(NO3)2 + H2SO4 (dil) ⟶ 2HNO3 + PbSO4 ↓ [white ppt. formed]
BaCl2 and Pb(NO3)2 are used for the above tests as they react with H2SO4 and form BaSO4 and PbSO4 respectively, which are the only compounds insoluble in dil. sulphuric acid.
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