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Informatics Practices

Give output for following SQL queries as per given table(s) :

Table : ITEM

I_IDItemNameManufacturerPrice
PC01Personal ComputerABC35000
LC05LaptopABC55000
PC03Personal ComputerXYZ32000
PC06Personal ComputerCOMP37000
LC03LaptopPQR57000

Table : CUSTOMER

C_IDCustomerNameCityI_ID
01N RoyDelhiLC03
06H SinghMumbaiPC03
12R PandeyDelhiPC06
15C SharmaDelhiLC03
16K AgarwalBangalorePC01

(i) SELECT DISTINCT City FROM Customer ;

(ii) SELECT ItemName, MAX(Price), Count(*)
FROM Item GROUP BY ItemName ;

(iii) SELECT CustomerName, Manufacturer
FROM Item, Customer
WHERE Item.I_ID = Customer.I_ID ;

(iv) SELECT ItemName, Price * 100
FROM Item WHERE Manufacturer = 'ABC' ;

SQL Queries

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Answer

(i)

Output
+-----------+
| City      |
+-----------+
| DELHI     |
| MUMBAI    |
| BANGALORE |
+-----------+

(ii)

Output
+-------------------+------------+----------+
| ItemName          | MAX(Price) | Count(*) |
+-------------------+------------+----------+
| LAPTOP            |      57000 |        2 |
| PERSONAL COMPUTER |      37000 |        3 |
+-------------------+------------+----------+

(iii)

Output
+--------------+--------------+
| CustomerName | Manufacturer |
+--------------+--------------+
| N ROY        | PQR          |
| H SINGH      | XYZ          |
| R PANDEY     | COMP         |
| C SHARMA     | PQR          |
| K AGARWAL    | ABC          |
+--------------+--------------+

(iv)

Output
+-------------------+-------------+
| ItemName          | Price * 100 |
+-------------------+-------------+
| LAPTOP            |     5500000 |
| PERSONAL COMPUTER |     3500000 |
+-------------------+-------------+

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