KnowledgeBoat Logo

Chemistry

Give balanced equations for the laboratory preparations of:

(i) A saturated hydrocarbon from iodomethane.

(ii) An unsaturated hydrocarbon from an alcohol.

(iii) An unsaturated hydrocarbon from calcium carbide.

(iv) An alcohol from ethyl bromide.

Organic Chemistry

12 Likes

Answer

(i) Methane is produced

CH3I methyl iodide+2[H] nascent hydrogenZn/Cu couplealcoholCH4 methane+HI\underset{\text{ methyl iodide}}{\text{CH}3\text{I}} + \underset{ \text{ nascent hydrogen}}{2\text{[H]}} \underset{\text{alcohol}}{\xrightarrow{\text{Zn/Cu couple}}} \underset{ \text{ methane}}{\text{CH}4} + \text{HI}

(ii) Ethene is formed

C2H5OH ethyl alcohol170°CConc. H2SO4[excess]C2H4ethene+H2O\underset{\text{ ethyl alcohol}}{\text{C}2\text{H}5\text{OH}} \xrightarrow[170\degree\text{C}]{\text{Conc. H}2\text{SO}4\text{[excess]}} \underset{ \text{ethene}}{\text{C}2\text{H}4} + \text{H}_2\text{O}\

(iii) Ethyne is formed

CaC2calcium carbide+2H2OwaterC2H2ethyne [acetylene]+Ca(OH)2\underset{\text{calcium carbide}}{\text{CaC}2} + \underset{\text{water}}{2\text{H}2\text{O}} \longrightarrow \underset{\text{ethyne [acetylene]}}{\text{C}2\text{H}2} + \text{Ca(OH)}_2

(iv) ethyl alcohol is formed.

C2H5-Br Bromoethane [ethyl bromide]+KOH [aq.] alcoholic KOHboilC2H5OH ethyl alcohol+KBr\underset{\text{ Bromoethane [ethyl bromide]}}{\text{C}2\text{H}5\text{-Br}} + \underset{\text{ alcoholic KOH}}{\text{KOH [aq.]}} \xrightarrow{\text{boil}} \underset{ \text{ ethyl alcohol}} {\text{C}2\text{H}5\text{OH}} + \text{KBr}

Answered By

6 Likes


Related Questions