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Chemistry

Give balanced equations for the electrode reactions involved in the following conversions at the respective electrodes:

  1. Aluminium oxide → Oxygen gas ← Copper [II] Sulphate
  2. Copper metal → Copper ions → Copper metal
  3. Lead [II] chloride → Chlorine gas ← Hydrochloric acid
  4. Hydroxyl ions ← Acidified water → Oxygen gas
  5. Potassium bromide → Bromine gas ← Lead bromide

Electrolysis

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Answer

  1. Aluminium oxide → Oxygen gas ← Copper [II] Sulphate

    Electrolysis of molten Al2O3:
    Al2O3 ⇌ 2Al3+ + 3O2-
    Reaction at anode:
    3O2- - 6e-⟶ 3[O]
    3[O] + 3[O] ⟶ 3O2 [product O2 gas]

    Electrolysis of copper (II) sulphate:
    CuSO4 ⇌ Cu2+ + SO42- [ions present]
    H2O ⇌ H1+ + OH1-
    Reaction at anode:
    OH1- - 1e-⟶ OH x 4
    4OH ⟶ 2H2O + O2 [product oxygen gas]
  2. Copper metal → Copper ions → Copper metal

    Reaction at anode:
    Cu – 2e- ⟶ Cu2+
    Reaction at cathode:
    Cu2+ + 2e- ⟶ Cu
  3. Lead [II] chloride → Chlorine gas ← Hydrochloric acid

    Electrolysis of molten PbCl2:
    PbCl2 ⇌ Pb2+ + 2Cl-
    Reaction at anode:
    2Cl- – 2e- ⟶ 2[Cl]
    Cl + Cl ⟶ Cl2

    Electrolysis of hydrochloric acid:
    HCl ⇌ H+ + Cl-
    Reaction at anode:
    2Cl- – 2e- ⟶ 2[Cl]
    Cl + Cl ⟶ Cl2
  4. Hydroxyl ions ← Acidified water → Oxygen gas

    Electrolysis of acidified water
    H2SO4 ⇌ 2H1+ + SO42-
    H2O ⇌ H1+ + OH1-
    Reaction at anode:
    OH1- - 1e- ⟶ OH x 4
    4OH ⟶ 2H2O + O2 [product oxygen gas]
  5. Potassium bromide → Bromine gas ← Lead bromide

    Electrolysis of molten KBr:
    KBr ⇌ K1+ + Br1-
    Reaction at anode:
    Br- – 1e- ⟶ Br
    Br + Br ⟶ Br2

    Electrolysis of molten PbBr2:
    PbBr2 ⇌ Pb2+ + 2Br-
    Reaction at anode:
    Br- – 1e- ⟶ Br
    Br + Br ⟶ Br2

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