Give balanced chemical equations for the following con­versions:

(i) Ethanoic acid to ethyl ethanoate.

(ii) Calcium carbide to ethyne.

(iii) Sodium ethanoate to methane.

(i) Ethanoic acid to ethyl ethanoate. :

$\underset{\text{ethyl alcohol}}{\text{C}$2\text{H}5\text{OH}} + \underset{\text{acetic acid}}{\text{CH}3\text{COOH}} \xrightarrow{\text{Conc. H}2\text{SO}4} \underset{\text{ethyl ethanoate}}{\text{CH}3-\text{COO}-\text{C}2\text{H}5} + \text{H}_2\text{O}

(ii) Ethyne is formed

$\underset{\text{calcium carbide}}{\text{CaC}$2} + \underset{\text{water}}{2\text{H}2\text{O}} \longrightarrow \underset{\text{ethyne [acetylene]}}{\text{C}2\text{H}2} + \text{Ca(OH)}_2

(iii) Sodium ethanoate to methane

$\underset{\text{sodium acetate}}{\text{CH}$3\text{COONa}} + \underset{\text{sodalime}}{\text{NaOH}} \xrightarrow[\Delta]{\text{CaO}} \underset{\text{methane}}{\text{CH}4} + \text{Na}2\text{CO}3