Give a balanced chemical equation for each of the following –

(i) Preparation of ethane from sodium propionate.

(ii) Action of alcoholic KOH on bromoethane.

(i) Ethane from sodium propionate : ethane is formed

$\underset{\text{sodium propionate}}{\text{C}$2\text{H}5\text{COONa}} + \underset{\text{sodalime}}{\text{NaOH}} \underset{\Delta}{\xrightarrow{\text{CaO}}} \underset{\text{ethane}}{\text{C}2\text{H}6} + \text{Na}2\text{CO}3

(ii) Ethyl alcohol is formed.

$\underset{\text{ Bromoethane [ethyl bromide]}}{\text{C}$2\text{H}5\text{-Br}} + \underset{\text{ alcoholic KOH}}{\text{KOH [aq.]}} \xrightarrow{\text{boil}} \underset{ \text{ ethyl alcohol}} {\text{C}2\text{H}5\text{OH}} + \text{KBr}