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Mathematics

Garima borrowed ₹ 40,000 at 10% p.a. simple interest. She immediately inverted this money at 10% p.a., compounded half-yearly. Calculate Garima's gain in 18 months.

Compound Interest

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Answer

For simple interest:

P = ₹ 40,000, R = 10 %, T = 1812\dfrac{18}{12} years

S.I.=P×R×T100=40,000×10×1812100=600,000100=6,000\text{S.I.} = \dfrac{P \times R \times T}{100}\\[1em] = \dfrac{40,000 \times 10 \times \dfrac{18}{12}}{100}\\[1em] = \dfrac{600,000}{100}\\[1em] = 6,000

Total amount to be paid at the end of 18 months = Borrowed amount + Interest = 40000 + 6000 = ₹ 46000

For compound interest:

P = ₹ 40,000, R = 102\dfrac{10}{2} % = 5 %, T = 1812×2\dfrac{18}{12} \times 2 = 3 years

A = P (1+R100)n\Big(1 + \dfrac{R}{100}\Big)^n

= 40,000 x (1+5100)3\Big(1 + \dfrac{5}{100}\Big)^3

= 40,000 x (1+0.05)3(1 + 0.05)^3

= 40,000 x (1.05)3(1.05)^3

= 40,000 x 1.157625

= 46,305

Compound Interest = Amount - Principal

= 46,305 - 40,000

= 6,305

Profit = Compound Interest - Simple Interest = ₹ 6,305 - 6,000 = ₹ 305

Hence, Garima's total gain in 18 months = ₹ 305.

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