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From the displacement-time graph of a cyclist, given in figure, find —

(i) The average velocity in the first 4 s,

(ii) The displacement from the initial position at the end of 10 s

(iii) The time after which he reaches the starting point.

From the displacement-time graph of a cyclist, given in figure, find The average velocity in the first 4 s, The displacement from the initial position at the end of 10 s, The time after which he reaches the starting point. Motion in one dimension, Concise Physics Solutions ICSE Class 9.

Motion in One Dimension

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Answer

(i) As we know,

Avg. velocity=Total distanceTotal time\text {Avg. velocity} = \dfrac {\text {Total distance}}{\text {Total time}}

Substituting the values from the graph, for the first 4 s, we get,

Avg. velocity=10m4s⇒Avg. velocity=2.5ms−1\text {Avg. velocity} = \dfrac {10 \text {m}}{4 \text {s}} \\[0.5em] \Rightarrow \text {Avg. velocity} = 2.5\text {ms} ^ {-1} \\[0.5em]

Hence, average velocity of the car is 2.5 ms-1.

(ii) From the graph, we get,

Displacement = final position - initial position

Substituting the values from the graph, for the first 10 s, we get,

Displacement = -10 - 0 = -10 m

Hence, displacement from the initial position at the end of 10 s = - 10 m

(iii) The cyclist would reach the start point two times, one at the 7 s and the other at 13 s.

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