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Chemistry

Four g of a metallic chloride contains 1.89 g of the metal 'X'. Calculate the empirical formula of the metallic chloride. [At. wt. of 'X' = 64, Cl = 35.5]

Stoichiometry

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Answer

4 g of metallic chloride contains 1.89 g of metal X

∴ 100 g of metallic chloride contains 1.894\dfrac{1.89}{4} x 100 = 47.25 g of metal X

∴ % of Cl in the metallic chloride = 100 - 47.25 = 52.75%.

Element% compositionAt. wt.Relative no. of atomsSimplest ratio
X47.256447.2564\dfrac{47.25}{64} = 0.7380.7380.738\dfrac{0.738}{0.738} = 1
Cl52.7535.552.7535.5\dfrac{52.75}{35.5} = 1.481.480.738\dfrac{1.48}{0.738} = 2

X : Cl = 1 : 2

Hence, empirical formula is XCl2

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