For data given in the adjoining table, the mean is : C.I. | f | x | u = (x - A)/i | f × u --- | --- | ---- | ---- | ----- 0-10 | 5 | | | 10-20 | 10 | | | 20-30 | 10 | | | 1. 17 2. 27 3. 25 4. 60

In the table, x is the mean value or class mark, i = class-size = 10, C.I. | f | x | u = (x - A)/i | f × u --- | --- | ---- | ---- | ----- 0-10 | 5 | 5 | (5 - 15)/10 = -10/10 = -1 | -5 10-20 | 10 | A = 15 | (15 - 15)/10 = 0/10 = 0 | 0 20-30 | 10 | 25 | (25 - 15)/10 = 10/10 = 1 | 10 Total | Σf = 25 | | | Σfu = 5 By formula, Mean = A + Substituting values we get : Mean = 15 + = 15 + 2 = 17. Hence, Option 1 is the correct option.

Find the mean (correct to one place of decimal) by using short-cut method.
x f
40 14
41 28
43 38
45 50
46 40
49 20
50 10

x	f
40	14
41	28
43	38
45	50
46	40
49	20
50	10

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The mean of given observations is :
C.I. f
30-40 2
40-50 3
41
27
71
91

C.I.	f
30-40	2
40-50	3

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The mean of observations, given in the adjoining table, is 20, the value of a is :
x f fx
10 10
20 a
30 10
20
30
10
25

x	f	fx
10	10
20	a
30	10

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If the mean of the data given in adjoining table is 20, the relation between x₁ and x₂ is :
x f fx
10 x₁
20 20
30 x₂
x₁ + x₂ = 30
x₁ - x₂ = 15
x₁ - x₂ = 0
x₁ + x₂ = 20

x	f	fx
10	x₁
20	20
30	x₂

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Mathematics

For data given in the adjoining table, the mean is :
C.I. f x u = (x - A)/i f × u
0-10 5
10-20 10
20-30 10
17
27
25
60

Statistics

Related Questions

Find the mean (correct to one place of decimal) by using short-cut method.
x f
40 14
41 28
43 38
45 50
46 40
49 20
50 10

The mean of given observations is :
C.I. f
30-40 2
40-50 3
41
27
71
91

The mean of observations, given in the adjoining table, is 20, the value of a is :
x f fx
10 10
20 a
30 10
20
30
10
25

If the mean of the data given in adjoining table is 20, the relation between x₁ and x₂ is :
x f fx
10 x₁
20 20
30 x₂
x₁ + x₂ = 30
x₁ - x₂ = 15
x₁ - x₂ = 0
x₁ + x₂ = 20

Mathematics

For data given in the adjoining table, the mean is :C.I.fxu = (x - A)/if × u0-10510-201020-301017272560

Statistics

Related Questions

Find the mean (correct to one place of decimal) by using short-cut method.xf4014412843384550464049205010

The mean of given observations is :C.I.f30-40240-50341277191

The mean of observations, given in the adjoining table, is 20, the value of a is :xffx101020a301020301025

If the mean of the data given in adjoining table is 20, the relation between x1 and x2 is :xffx10x1202030x2x1 + x2 = 30x1 - x2 = 15x1 - x2 = 0x1 + x2 = 20

For data given in the adjoining table, the mean is :
C.I. f x u = (x - A)/i f × u
0-10 5
10-20 10
20-30 10
17
27
25
60

Find the mean (correct to one place of decimal) by using short-cut method.
x f
40 14
41 28
43 38
45 50
46 40
49 20
50 10

The mean of given observations is :
C.I. f
30-40 2
40-50 3
41
27
71
91

The mean of observations, given in the adjoining table, is 20, the value of a is :
x f fx
10 10
20 a
30 10
20
30
10
25

If the mean of the data given in adjoining table is 20, the relation between x₁ and x₂ is :
x f fx
10 x₁
20 20
30 x₂
x₁ + x₂ = 30
x₁ - x₂ = 15
x₁ - x₂ = 0
x₁ + x₂ = 20