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Chemistry

Following questions refer to one mole of chlorine gas.

(a) What is the volume occupied by this gas at S.T.P.?

(b) What will happen to the volume of gas, if pressure is doubled?

(c) What volume will it occupy at 273°C?

(d) If the relative atomic mass of chlorine is 35.5, what will be the mass of 1 mole of chlorine gas?

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Answer

(a) According to Avogadro's law : The volume occupied by 1 mole of chlorine is 22.4 dm3

(b) According to Boyle's Law: PV = constant

Hence, if pressure is doubled then volume will become half i.e. 22.42\dfrac{22.4}{2} = 11.2 dm3

(c) V1 = 22.4 dm3

T1 = 273 K

T2 = 273 + 273 K = 546 K

V2 = ?

According to charles law:

V1T1\dfrac{\text{V}1}{\text{T}1} = V2T2\dfrac{\text{V}2}{\text{T}2}

Substituting to we get,

22.4273\dfrac{ 22.4}{273} = V2546\dfrac{\text{V}_2}{546}

Hence, V2 = 22.4273\dfrac{ 22.4}{273} x 546 = 44.8 dm3

(c) Mass of 1 mole Cl2 gas = 35.5 × 2 = 71 g

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