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In the following figure, l // m // n. If OC = OD = 5 cm, OA = 8cm and OE = 10 cm, find OB and OF.

In the following figure, l // m // n. If OC = OD = 5 cm, OA = 8cm and OE = 10 cm, find OB and OF. Chapterwise Revision (Stage 1), Concise Mathematics Solutions ICSE Class 9.

Mid-point Theorem

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Answer

In Δ OAC and Δ OBD,

∠AOC = ∠DOB (Vertically opposite angles)

∠OCA = ∠ODB (Alternate angles of parallel lines)

∠OAC = ∠OBD (Alternate angles of parallel lines)

By AAA rule,

Δ OAC ~ Δ OBD

Thus, OAOB=OCOD\dfrac{OA}{OB} = \dfrac{OC}{OD}

8OB=55\dfrac{8}{OB} = \dfrac{5}{5}

8OB=1\dfrac{8}{OB} = 1

⇒ OB = 8 cm

Similarly, in Δ OEC and Δ OFD,

∠EOC = ∠DOF (Vertically opposite angles)

∠OCE = ∠ODF (Alternate angles of parallel lines)

∠OEC = ∠OFD (Alternate angles of parallel lines)

By AAA rule,

Δ OEC ~ Δ OFD

Thus, OEOF=OCOD\dfrac{OE}{OF} = \dfrac{OC}{OD}

10OF=55\dfrac{10}{OF} = \dfrac{5}{5}

10OF=1\dfrac{10}{OF} = 1

⇒ OF = 10 cm

Hence, OB = 8 cm and OF = 10 cm.

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