Five cards Ten, Jack, Queen, King and Ace of diamonds are shuffled face downwards. Then one card is picked at random.

(i) What is the probability that the card picked is queen ?

(ii) If a king is drawn first and put aside, what is the probability that the second card picked up is the ace ?

(i) No. of cards = 5.

∴ Total number of possible outcomes = 5.

No. of queen cards = 1

∴ No. of favourable outcomes = 1

P(drawing a queen) = $\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{1}{5}$.

Hence, the probability of drawing a queen = $\dfrac{1}{5}$.

(ii) Since, king is drawn and put aside.

No. of cards left = 4.

∴ Total number of possible outcomes = 4.

No. of ace cards = 1

∴ No. of favourable outcomes = 1

P(drawing an ace) = $\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{1}{4}$.

Hence, the probability of drawing an ace = $\dfrac{1}{4}$.