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Mathematics

Find the value of:

sin2 30° + cos2 30° + cot2 45°

Trigonometric Identities

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Answer

sin230°+cos230°+cot245°=(12)2+(32)2+(1)2=14+34+1=1+34+1=44+1=1+1=2\text{sin}^2 30° + \text{cos}^2 30° + \text{cot}^2 45° = \Big(\dfrac{1}{2}\Big)^2 + \Big(\dfrac{\sqrt3}{2}\Big)^2 + (1)^2\\[1em] = \dfrac{1}{4} + \dfrac{3}{4} + 1\\[1em] = \dfrac{1 + 3}{4} + 1\\[1em] = \dfrac{4}{4} + 1\\[1em] = 1 + 1\\[1em] = 2

Hence, sin2 30° + cos2 30° + cot2 45° = 2.

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