Find three consecutive odd integers , the sum of whose squares is 83.

Let the required numbers be x , x + 2 , x + 4. Given, the sum of squares of these numbers = 308 ∴ When x = -7 , x + 2 = -5 , x + 4 = -3 and when x = 3 , x + 2 = 5 , x + 4 = 7. Hence , the required numbers are -7, -5, -3 and 3, 5, 7.