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Mathematics

Find the value(s) of p for which the quadratic equation 2x2 + 3x + p = 0 has real roots.

Quadratic Equations

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Answer

For real roots, Discriminant ≥ 0

or , b2 - 4ac ≥ 0

The above equation is 2x2 + 3x + p = 0
Comparing with ax2 + bx + c = we obtain,
a = 2 , b = 3 , c = p

Putting values in b2 - 4ac ≥ 0 we get,

=324×2×p0=98p098p8p9p98= 3^2 - 4 \times 2 \times p \ge 0 \\[0.5em] = 9 - 8p \ge 0 \\[0.5em] \Rightarrow 9 \ge 8p \\[0.5em] \Rightarrow 8p \le 9 \\[0.5em] \Rightarrow p \le \dfrac{9}{8} \\[0.5em]

Hence the value of p is ≤ 98\dfrac{9}{8}.

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