Find the slope of the line which is parallel to $\dfrac{x}{2} - \dfrac{y}{3} - 1 = 0$

Given,

$\Rightarrow \dfrac{x}{2} - \dfrac{y}{3} - 1 = 0 \\[1em] \Rightarrow \dfrac{y}{3} = \dfrac{x}{2} - 1 \\[1em] \Rightarrow y = \dfrac{3}{2}x - 3.$

Comparing above equation with y = mx + c we get,

Slope = $\dfrac{3}{2}$

Since, slope of parallel lines are equal.

Hence, slope of line parallel to $\dfrac{x}{2} - \dfrac{y}{3} - 1 = 0$ is $\dfrac{3}{2}$.