Find the position and magnification of the image of an object placed at distance of 8.0 cm in front of a convex lens of focal length 10.0 cm. Is the image erect or inverted?

i) As the image is formed on the other side of the lens, so the image is real. Hence, the lens is convex. As we know, the lens formula is Given, f = 10 cm u = - 8 cm Substituting the values in the formula, we get, Therefore, the image is formed 40 cm in front of the lens. ii) As we know, the formula for magnification of a lens is Given, u = –8 cm v = -40 cm Substituting the values in the formula, we get, Therefore, the magnification is +5.0 As the magnification is positive so the image is erect.

The magnification by a lens is -3. Name the lens and state how are u and v related?

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The magnification by a lens is +0.5. Name the lens and state how are u and v related?

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A concave lens has a focal length of 30 cm. Find the position and magnification (m) of the image for an object placed in front of it at a distance of 30 cm. State whether the image is real or virtual ?

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The power of a lens is -2.0 D. Find its focal length and its kind.

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Physics

Find the position and magnification of the image of an object placed at distance of 8.0 cm in front of a convex lens of focal length 10.0 cm. Is the image erect or inverted?

Refraction Lens

Related Questions

The magnification by a lens is -3. Name the lens and state how are u and v related?

The magnification by a lens is +0.5. Name the lens and state how are u and v related?

A concave lens has a focal length of 30 cm. Find the position and magnification (m) of the image for an object placed in front of it at a distance of 30 cm. State whether the image is real or virtual ?

The power of a lens is -2.0 D. Find its focal length and its kind.