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Chemistry

Find the molecular formula of a hydrocarbon having vapour density 15, which contains 20% of Hydrogen.

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Answer

Element% compositionAt. wt.Relative no. of atomsSimplest ratio
Carbon80128012\dfrac{80}{12} = 6.666.666.66\dfrac{6.66}{6.66} = 1
Hydrogen201201\dfrac{20}{1} = 20206.66\dfrac{20}{6.66} = 3

Simplest ratio of whole numbers = C : H = 1 : 3

Hence, empirical formula is CH3

Empirical formula weight = 12 + 3(1) = 15

V.D. = 15

Molecular weight = 2 x V.D. = 2 x 15

n=Molecular weightEmpirical formula weight=2×1515=2\text{n} = \dfrac{\text{Molecular weight}}{\text{Empirical formula weight}} \\[0.5em] = \dfrac{2 \times 15}{15} = 2

∴ Molecular formula = n[E.F.] = 2[CH3] = C2H6

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