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Mathematics

Find the mode and median of the following frequency distribution :

xf
101
114
127
135
149
153

Measures of Central Tendency

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Answer

The variates are already in ascending order. We construct the cumulative frequency table as under :

xfCumulative frequency (C.F.)
1011
1145
12712
13517
14926
15329

Total number of observations = 29, which is odd.

Median=n+12th observation=29+12=302=15th observation\therefore \text{Median} = \dfrac{n + 1}{2} \text{th observation} \\[1em] = \dfrac{29 + 1}{2} \\[1em] = \dfrac{30}{2} \\[1em] = 15 \text{th observation}

All observations from 13th to 17th are equal, each = 13, so median = 13.

As the variate 14 has maximum frequency 9, so mode = 14.

Hence, median = 13 and mode = 14.

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