Mathematics
Find the equation of the line whose slope is and which passes through (-3, 4).
Straight Line Eq
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Answer
By point-slope form,
Equation of line : y - y1 = m(x - x1)
Substituting values we get,
⇒ y - 4 = [x - (-3)]
⇒ 3(y - 4) = -4(x + 3)
⇒ 3y - 12 = -4x - 12
⇒ 4x + 3y = -12 + 12
⇒ 4x + 3y = 0.
Hence, equation of line is 4x + 3y = 0.
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