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Mathematics

Find the equation of the line whose slope is 43-\dfrac{4}{3} and which passes through (-3, 4).

Straight Line Eq

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Answer

By point-slope form,

Equation of line : y - y1 = m(x - x1)

Substituting values we get,

⇒ y - 4 = 43-\dfrac{4}{3}[x - (-3)]

⇒ 3(y - 4) = -4(x + 3)

⇒ 3y - 12 = -4x - 12

⇒ 4x + 3y = -12 + 12

⇒ 4x + 3y = 0.

Hence, equation of line is 4x + 3y = 0.

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