Find the equation of a straight line perpendicular to the line 3x - 4y + 12 = 0 and having same y-intercept as 2x - y + 5 = 0.

Given equation of line, ⇒ 3x - 4y + 12 = 0 Converting it in the form y = mx + c, ⇒ 4y = 3x + 12 ⇒ y = . Comparing with y = mx + c we get, Slope (m 1 ) = . Let the slope of the line perpendicular to the given line be m 2 . So, m 1 × m 2 = -1 The other line is 2x - y + 5 = 0 or y = 2x + 5. Comparing with y= mx + c we get, c = 5. So, the new line has slope = and y-intercept = 5. Putting these values in y = mx + c, Hence, the equation of the line is 4x + 3y - 15 = 0.

Find the equation of a line, which has the y-intercept 4, and is parallel to the line 2x - 3y - 7 = 0. Find the coordinates of the point where it cuts the x-axis.

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Find the equation of a straight line perpendicular to the line 2x + 5y + 7 = 0 and with y-intercept -3.

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Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0.

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Write down the equation of the line perpendicular to 3x + 8y = 12 and passing through the point (-1, -2).

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Mathematics

Find the equation of a straight line perpendicular to the line 3x - 4y + 12 = 0 and having same y-intercept as 2x - y + 5 = 0.

Straight Line Eq

Related Questions

Find the equation of a line, which has the y-intercept 4, and is parallel to the line 2x - 3y - 7 = 0. Find the coordinates of the point where it cuts the x-axis.

Find the equation of a straight line perpendicular to the line 2x + 5y + 7 = 0 and with y-intercept -3.

Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0.

Write down the equation of the line perpendicular to 3x + 8y = 12 and passing through the point (-1, -2).